Maths for RMS and Sainik Entrance

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Defence Academy Coimbatore A leading coaching academy for Sainik, Military and RIMC Schools, NDA, IMA, AFCAT SSB, FSB Interview http://www.ssbcoaching.com call 094437 20076


All India Sainik School Entrance Examination-2013
Paper - I - Mathematics and Language Ability- Class VI


Time: 2 Hours                                                                                                                                                                                                                                                  Maximum Marks 200

PART A MATHEMATICS- SECTION - 1

(Each question carries two marks)

Q.1. Find the lowest Common multiple of 2, 4 and 5 Solution:-

  • Step 1: Find the factors of 2, 4 and 5
  • Step 2: The factors of 2 = 1 and 2
  • The factors of 4 = 1, 2 and 4 Or (1 *2 *2)
  • The factors of 5 = 1 and 5
  • Step 3: Taking the common factors of these we get: 1 * 2 * 2* 5 Find the factors of 2, 4 and 5
  • Step 4: To find the LCM of 2, 4 and 5 we will mulitply the common factors i.e.1* 2 *2 * 5 = 20
  • Step 5: Therefore the LCM of 2, 4 and 5 is 20 (Answer)
    •  Q.2. What least number should be added to 322516 so that the result is exactly divisible by 543?
    Solution:-

  • Step 1: First find: 322516 Divided by 543 = ?
  • Step 2: Method: Divide and subtract the remainder from 543. the answer is to be added to 322516
  • On dividing 322516 by 543 we get a remainder of 517
  • To make the given number exactly divisible by 543 we have to add 26 to the Main number
  • Step 3: This we get by subtractring the remainder from the number 543i.e 543-516 - 26
  • Step 4: By adding we getg 322516 + 26 =322542, this is exactly divisible by 543
  • Step 5: Therefore the Leat num ber to be added is 26 (Answer)

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