SAINIK- RMS CLASS VI REVISION MATHS

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vIf 2 apples each weight 150 grams cost Rs.15, what would be the cost of 2 and 3/4 kg of apples?
This is an application based question. ( Unitary Method)
Q.No
Step
Q
Remarks
1
Step: 1
What is the data given in the Problem
Cost of 2 apples each weight 150 grams cost Rs. 15


Deduction : total weight of apples=
300 grams
300 grams cost Rs. 15

Step 2
To find the cost of 2 ¾ kg of apples


Step 3
Is any conversion required?
Yes convert kg into grams
Because the question asks for cost

Step 4
Formula
Unitary Method, find the cost of 100 grams and multiply with the cost of 2750 grams



100 grams ------ Rs. 5
2750 grams------X



100 *  x = 2750 x 5
X = ( 2750 x 5 ) / 100 =  13750/ 100 = Rs.137.50

Step 5
Answer:  Therefore cost of 2 ¾ kg of apples=
Rs. 137.50

Q.2 Solution:
A car is moving at an average speed of 36 and 4/5 km/h.
How much distance will it cover in 7 ½ hours?
Sol.
Distance covered by the car in 1 hour= 36 and4/5 km
Distance covered by the car in 7 ½ hours = 276 km
Distance covered by the car in 1 hour= 36and 4/5 hours = 154/ 5

km.Distance covered by the car in 7 1/2 = 15 / 2

ie =(184 /5) *(15/ 2)= 276 km.
Hence, the required distance is 276 km.

Q.3. The sum of two consecutive numbers is 53. Find the numbers
To do this there are two methods:
Sol.
Let one number be x. Then, the next consecutive numberis x + 1. It is given that the sum of two consecutivenumbers is 53. So, we obtain the following equation :x + (x + 1) = 53

2x + 1 = 53

2x = 53 -1  [On transposing 1 on R.H.S.]

2x/2 = 52/2 = 252  [Dividing both sides by 2]

x = 26

One number = 26
Another number = 26 + 1 = 27.

Second Method:
Sum of two consecutive numbers = 53
Ie 53/ 2 = 26.5
Since it is two consecutive numbers  should be 26 and 27 =  (ie  26 + 27 = 53)

Twelve years hence a man will be four times as he was twelve years ago, then his present age is :

Let the present age be x
x-12 = 4( x+12)
x – 12 = 4x + 48
or 4x – x = 48 +12
3x = 60
Hence x 60/3 = 20 years ( as on today) Answer


Two men work for 8 hours  a day to complete the project in 40 days. If  one man has to do the same task working for 12 hours a day, how long ( how many days) will he take to complete the task?
Solution:
One man 8 hours x 40 = 320 hours + 320 hours = 640 hours
640/12 = 53.33  days.

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