Free Maths revision test for sainik -rms class vi
There will be 30 questions in this section. Please read the questions carefully and
answer them
Each question carries 3 marks 3x 33 = 99 neatness carries 01
mark
The answer sheet should be drawn with pen and use the foot
ruler. On the top write
Name___________________ Date________________ Start
Time______________ Finish Time________
Q.No: |
Your Answer |
Correct Answer |
Marks |
Remarks |
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Why Did I go wrong in the Question? Where was the mistake?
Q.No |
Question |
Remarks |
1 |
What is the SUCCESSOR of the greatest number of 5 digits formed
with the digits 6,9,0,2,1 |
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2 |
The difference between the place and face value of 3 in 232001
is__________ |
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3 |
In the following which is the greatest number? (a) (4)^2, (b) [(2+2)^2]^2, (c) (2 x 2 x 2)^2, (d) (2 + 2 + 2)^2, e) (2+2
x 2 +2)^2 |
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4 |
A student multiplied 7236 by 65 instead of multiplying by 56. By how
much was his answer greater than the correct answer? (Sainik School - 2019) |
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5 |
(5967 - 2437 -1910) Divided by? = 27 |
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6 |
15-10+5x2 ÷5 |
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7 |
(10 x 10 x10) ÷ (20÷10 x10 – 10) +6 = ? |
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8 |
___________________ Ö5² +41X5 -17² -75 = ? |
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9 |
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10 |
1150 ÷50 ÷23 +15 = ? |
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11 |
Viky had Rs.250. He spent Rs.50
on the books. Find his percent expenditure. |
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12 |
If 90% of A =30% if B and
B = x% of A , then the value of x is |
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13 |
If 6 men can do a job in 10
days, then in how many days 4 men will do the same job? |
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14 |
The cost of 5 tables is the
same as the cost of 7 chairs. If the cost of one table is Rs.210 find the
cost of a chair. |
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15 |
How many meters of cloth at
Rs.3.50 per meter will be exchanged by a cloth merchant for Rs.7 kg of tea at
the rate of Rs.28 per kg? |
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16 |
A Cricket player scores 13, 0,
19, 17, 6 & 11 runs in different matches. Find his average |
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17 |
The average age of 30 students
in a 4 classes is 15 years. If 16 students of this class have the average age
of 16 years, then find the average age of remaining 14 students |
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18 |
The average of three numbers is
24, if one of the numbers is 18 and the other number is 19, find the third
number. |
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19 |
Duration
of sunshine in Aligarh city for one week of August 2002 are given as 12.20
hours, 12.18 hours, 12.17 hours, 12.15 hours, 12.13 hours, 12.12 hours, 12.10
hours. Find the average duration of sun shine. |
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20 |
The average of two numbers is 5. One of the
two numbers is four times as big as the other. What are these two numbers? |
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21 |
Ramesh had rs.250. He spent Rs.50
on books. Find his percent expenditure. |
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22 |
Find 5 % of Rs.200 + 10% of
Rs.250 |
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23 |
The population of a certain
town has increased from 60,000 to 65,000. Find the increase percent. |
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24 |
A's salary is 80% of B's
salary. If B's salary is Rs.14,600, find A's salary. |
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25 |
Convert 0.4 into percent and
2.75 as percent |
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26 |
Profit and Loss A man bought 75 m of cloth at
Rs.18 per metre. At what rate per metre should he sell the cloth so as to
gain Rs.150? |
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27 |
Mohan
purchased a Cell Phone for Rs. 10,000. he paid Rs.150 as tax and Rs.100
recharge at what price must he sell it to gain 20 % |
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28 |
By selling a plot of land for
Rs. 17250, Raj gains 5%. For how much should he sell the plot to gain 15% in
the transaction? |
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29 |
Two horses were
sold for Rs.12,000 each,on eat a loss of 20% and the other at a gain of
20%. The entire transaction resulted in : |
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30 |
The cost price of 20 articles
is the same as the selling price of x articles.If the profit is 25%,
then the value of x is :
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Answer
Q.No: |
Answer |
Explanation |
1 |
96211 |
The answer is 96210 +1 ( Successor) = 96211 is the Correct answer |
2 |
29997 |
30000 – 3 = 29997 |
3 |
B |
[(2+2)^2]^2 [(4)^2} = (16)^2 =
256
4^2 = 16 (2x2x2)^2
= (8)^2 = 64 (2+2+2)
^2 = (6)^2 = 36 (2+2x2+2)^2 = (2+4+2)^2 =(8)^2 = 64 |
4 |
65124 |
Multiply 7236 by 65 = (7236
x65) –( 7236 x 56) By taking out the common number we get 7236( 65-56) 7236 x 9 = 65124 |
5 |
60 |
By simplification using BODMAS we get 1620 / x = 27 OR x = 1620 / 27 = 60 answer |
6 |
7 |
15-10 +5 x 2 divided by 5 = 15-10 +5 x 2/5 = 17 -10 = 7 |
7 |
106 |
10 x10 x 10 Divided by (20/10 x 10 -10) + 6 = 1000 Divided by (20-10) +6 1000 Divided by 10+6 100 +6 = 106 |
8 |
69 |
Ö
24 X41 X5 -17 X17 -75 = Ö
5125 - 289 -75 =Ö
4761 = 69 |
9 |
9 1/30 |
|
10 |
16 |
1150/50 ÷13+15 = 23÷23 +15 = 1+15 = 16 Answer |
11 |
|
Out of Rs. 250 the expenditure is
Rs.50 our out of Rs.1m the expenditure
is 50/250 Hence, out of Rs.100, the expenditure
= (50 x100) / 25 = 20 % |
12 |
Rs.300 |
solution: 900/100 A = 30/100
B = 30/100 * x/100 A x = 90/100 x (100 *100) / 30 =
Rs.300 |
13 |
15 Days |
6 men can do a job in 10 days,
hence, 1 man can do the same job in 6 x10 = 60 days Therefore 4 men can do the same
job in 60 divided b4 = 15 Days |
14 |
Rs.150 |
Cost of 5 tables = Cost of 7
chairs,& cost of 1 table is Rs.210, so, cost of 5 Tables=210x 5=
Rs.1050 Therefore cost of 7 Chairs=Rs1050,
Hence Cost of 1 chair= 1050 Divided by 7 = Rs.150 Answer |
15 |
Rs.56. |
Cost of 1 kg of tea= Rs.28, and
Cost of 7 kg of Tea= Rs.28 x 7 = Rs.196 Cost of 1 m of cloth= Rs.3.50,
Therefore for 196 we get cloth @Rs.3.50 p/mtr= 196/ 3.50 = 56 m |
16 |
10 Runs |
Average= Sum of all / Total innings = 13+0+19+17+11 =60 / 6 = 10 Runs |
17 |
13.85 years |
Average age of 30 students = 15
years. hence total age= 30 x 15 = 450 years Average age of 16 students =
16years, hence total age = 16 x 16 = 256 Years Total age of remaining 14
students = 450 - 256 = 194 years Hence, average age of 14 students
= 194/ 14 = 13.85 years Answer |
18 |
35 |
24 x3 = 72 & 18+19 = 37, hence the
Dif = 35 is the third number |
19 |
12.15 hours |
Total duration of sun shine =
12.20 + 12.18 + 12.17 + 12.15 + 12.13 + 12.12 + 12.10 = 85.05 hours. Number of days = 7 Therefore, average duration of
sunshine = 85.05/7 = 12.15 hours. |
20 |
8 |
5x2 =10 total one numbers x, the other number is 4 x 5x =10 x
=2 so 2 and 8 |
21 |
20% |
Out of Rs.250. Expenditure=
Rs.50, Therefore out of Rs.100 -Expenditure =x Hence, x = 100 x 50 / 250 = 20 % |
22 |
Rs.35 |
5% of 200 =
5/100 *200 = Rs.10,10% of Rs.250 = 10/100 * 250 = Rs.25 Total = Rs.10+Rs.25 = Rs.35
answer |
23 |
8 1/3% |
Increase in population = 65000 -
60000 = 5000 percentage of increase = for
60000 it is 5000 Hence for 100 it would
be x Cross multiply 5000 x 100 / 60000 = 5 x 10/ 6 =
25/3 = 8 1/3 % of 8.33 % |
24 |
Rs.11,680 |
Let the salary of A be
Rs.80. then B's salary is Rs. 100 Hence is 100% = Rs. 14,600, then
80% = x Cross multiply (80x 14,600) / 100
= 80 x 146 = Rs.11,680 Answer |
25 |
40% and 275% |
0.4 = 4/10 = 4 x100 / 10 x100 =
40/100 = 40% 2.75 = 275 x100 / 100 x100 = 275
/100 = 275% |
26 |
Rs.1500 |
75 for Rs.1500 |
27 |
Rs.12300 |
10000 +15)+100 = Rs. 10250 , gain
20% SP = 120/100 x 10250 = Rs. 12300 |
28 |
Rs.18860 |
|
29 |
Loss Rs.100 |
Total
selling price=12000×2=24000
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30 |
|
Cost price
of 20 articles =selling price of x articles
⇒20×c.p=x×s.p .........(1)
Profit =25% Profit=S.P−C.P
Profit %=C.PS.P−C.P×100=25 ⇒C.PS.P=1=41
⇒x20−1=41 (∵ from (1)) ⇒x20=45
⇒x=16.
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