RIMC- DEC 2017 Entrance Exam Preparation Kit by Defence Academy

Defence Academy Coimbatore A leading coaching academy for Sainik, Military and RIMC Schools, NDA, IMA, AFCAT SSB, FSB Interview http://www.ssbcoaching.com call 094437 20076

How we solve the mathematics- step by step a sample

                                                    
RIMC 2015 Dec Maths Solution

Q.1. Compare the Rational number 13 / -8 and -27 / 12
Solution
1
13/ -8  can be written as
 -1.625

And  -27 / 12 can be written as
- 2.25
Answer
Hence the greater number is
-1.625 of 13 /-8

Q.2. Express in Power notation: -625 / 14641
2
- 625 / 14641 can be written as
-625 = ( -25) ( 25) of     5-4

And 14621 can be written as
121 x 121 or 114
Answer
Therefore -615 / 14641
5-4/  114

Q.3. Find the volume of the cuboid whose length, breadth and height are 8m , 70 cm, 90 cm
3
Given
L = 8m, B = 70 cm and H = 90 cm

To find Volume


Formula to be used
L x b x h ( since one qty is in m and other sin cm , there is a need  to convert all the qty in same unit. Ie. Cm to m
1 m = 100 cm


Hence 8 x 100 = 800 cm ( length)

Substituting the values in the formula we get
800 x 70 x90 = 5040000 cubic cm
Or 5.04 cubic m

Q.4. a) Find the value of “a” if 8a = 352- 272
4
Given
8a =352- 272


To find Value of ‘a’


Formula to be used
The sum is in the form of (a2-b²) or ( a+b) ( a-b)




Substituting the values in the formula we get
(35² ) – ( 27²)
This can be written as  ( 35 + 27) ( 35-27)
Ie. (62) x (8) = 496

Working:
As per sum 8 a = 496 or a = 496 / 8 = 62

Answer
Therefor the value of a = 62

Q.4. (b) Simplify (132²-122²)
4 b
Given
Simplify (132²-122²)





Formula to be used
The sum is in the form of (a2-b²) or ( a+b) ( a-b)




Substituting the values in the formula we get
(132² ) – ( 122²)
This can be written as  (135 + 122) ( 135-122)
Ie. (257) x (13) = 3341

Working:
 Ie. (257) x (13) = 3341

Answer
3341
               
Q.5. The areas of three circles are in the ratio 4 : 9 : 25.  Find the ratio of their radii.

5
Given
Ratio of three circles  4 : 9 : 25

Formula to be used
Area of a circle is given by the formula   pie x r x r




Substituting the values in the formula we get
Since pie value is same  we have ( RADIUS X RADIUS) : ( RADIUS X RADIUS) :  ( RADIUS X RADIUS) OR 2 : 3 : 5

Working:
 On deduction we get the ratio of the radii as 2 : 3: 5

Answer
2 : 3 : 5

Q.6. If the selling price of an article is 4/ 3 of its cost price. Find its profit percent.
6
Given
Sp of an article is 4/3 of it cost price

To find the
Cost Price

Formula to be used
SP – CP = Profit
Profit % = (Gain / CP ) x 100

Substituting the values in the formula we get
Let us 100 as CP
Then 4/ 3 of  100  = 4x 33.3 = 133.33
Then CP is 100 hence profit is 33.33

Working:
Profit % = Gain / CP x 100
= 33.33 / 100 x 100= 33.33 %

Answer
Profit is 33.33%

Q.7. Find the measure of the angels marked x, y and z.  Triangle ABC is an equilateral Triangle.
7
Given
Triangle ABC is an Equilateral Triangle.

Deduction
In an equilateral Triangle all angles will be 60 degrees and all sides equal

Given
Angle “O” is 40 degrees and, angle B if ADB is standing on line DBC is 180 degree
180 – 60 = 120 ie  Angle x + D + B = 180.
In this angle D= 40 degrees and  angle B = 60 degrees hence angle x = 180 =100  = 80 degrees.
Angel z = 60 degree and angle Y =60 + 30 = 90  hence 180=90 = 90 degrees


 Defence Academy Coimbatore A leading coaching academy for Sainik, Military and RIMC Schools, NDA, IMA, AFCAT SSB, FSB Interview
Study kit available
10 books that would help you to succeed
www.ssbcoaching.com 
call 094437 20076
 

Comments

Popular posts from this blog

RIMC December 2017 General Knowledge Solved paper

GK Questions for RIMC- RMS Compiled by www.sainikrimc.com

Picture Perception - Model story