15 days countdown questions of Sainik School- RMS Class VI Entrance Examination - Target 2016-17
ssb- sainik- rms- rimc coaching academy
call 0944 3720076
Formula Based Revision
Test
Five marks per
question 5 sums in each chapter.
class VI
I.Simplification
Q. 1. Find the value of 1+ [1+1+ {1+1+ (1+1+2)}]
Q.2. [3 + (3 x 3) ÷ 3] / [4+ (4+4) ÷4]
Q.3.
(69 – 14 x 3 ÷ 2) / (9 x 5-5 x 5)
Q.4.48
÷ 12 x (9/8 of 4/3 ÷ ¾ of 2/3) is equal to
Q.5.
the value of 4/8, 7/8 and 4/ 9 is
II.Square Root:
Q.5.
Find the Square root of 576 (By Prime Factorization Method)
Q.6
Find the Square Roots and Add √256 + √169 =?
Q.7.
which of the following cannot be a digit at the unit place of a perfect square?
a) 1 b) 5 c) 7 d) 0
Q. 8
If x =4, then x² =?
Q.9. the
least perfect square number exactly divisible by 4, 5, 6, 15 and 18 is__
(a)
800 (b) 225 (c) 361 (d)
900
Q.10.
the largest Three digit numbers, which is prefect square is______
(a)
961 (b) 925 (c) 930 (d)
950
III. LCM & HCF
Q.11.
Find the L.C.M of 12, 15 and 21
Q.12.
Four bells ring at an interval of 6, 7, 8 and 9 seconds respectively. All the
bells ring together after____ seconds.
Q.13.The
least number which when decreased by 7 is exactly divisible by 12, 16, 18, 21
and 28 is_____
Q.14.
The LCM of two number is 2, and their HCF is 2. If one the two numbers is 6
then the other number is___
Q.15.
The greatest number that will divide 137, 182 and 422 leaving a remainder of 2
in each case is
Day 02 Tests
a) BODMAS
b) Unitary Method
c) Average
For complete set and on line exam call
094437 20076
We have detailed step by step solution in our hard Copy
Rs. 2750 only
On line tests for Sainik School and RMS will be available shortly
For one year long coaching classes contact
094437 20076
Answers: Count down test series.
|
Q.No
|
Answer
|
Remarks
|
|
1
|
5/
8
|
|
|
2
|
1
|
|
|
3
|
1.45
|
|
|
4
|
12
|
|
|
5
|
7/36
|
|
|
|
Square
roots
|
|
|
6
|
24
|
√576
= (2 x 2) x (2 x 2) x (2 x 2) x (3 x 2)
Or
2
x 2x 2 x 3 = 24
|
|
7
|
16
+ 13 = 29
|
|
|
8
|
7
|
|
|
9
|
16
|
|
|
10
|
961
|
|
|
|
LCM
and HCF
|
|
|
11
|
420
|
LCM of 12, 15, 21 =
3 x 4 x 5x 7 = 420
|
|
12
|
504 Seconds
|
Find the LCM of the
numbers. 6, 7, 8 and 9( time Interval
ie. 2 x 3x 7x 4 x 3 = 504
|
|
13
|
1005
|
Find the LMC of
12.16.18. 21 and 28 and add 7 to it, is. 1008 + 7 = 1015
|
|
14
|
8
|
LCM x HCF / On the
two numbers is the other number.
|
|
15
|
15
|
137 -2 = 135, 182 –
2 = 180 and 422 -2 = 420
HCF of these number
is 15 Answer
|
Comments
Post a Comment