Free Revision Test maths class VI entrance Sainik and RMS

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19 Oct Revision Test  Class VI maths Duration  1hour-20 questions 5 marks each

1. Find the SUM and DIFFERENCE between the Greatest and Smallest number that can be formed from the following 6 numbers using them only once. 9, 3, 0, 4, 1, 8

2. Write in Roman Numerals a) 99, b) 1009

3. If you switch the positions of the digits 3 and 5 in the number 3256, which statement is correct?
A) the number does not change,   -- b) the number increases

C)    the number decreases,          d) the number has more digits

4. Two numbers N and 16 have LCM = 48 and GCF = 8. Find N.

(Hint we know the Product of two number = LCM x HCF)

5. A machine fills 150 bottles of water every 8 minutes. How many minutes it takes this machine to fill 675 bottles?

6. Tim had lunch at Rs.50.50 and he gave 20% tip, how much did he spend (Total money)?

7. Find the LCM of 1240 and 5300 using prime factorization.

8. Find the GCF of 20 and 24 using prime factorization

9. Find the smallest number which when divided by 4 12 16 and 20 leaves no remainder

10. CP and SP-  Find the Final cost price of a Car. ( Your purchase prize was Rs.85,000, You put fuel for Rs. 3.500, and got the car repaired for Rs. 6,500.) Hence your cost price is Rs.________  and you wanted to make 10 % profit on selling it. Hence yours SP would be  Rs. ________

11. Four workers worked for 6 hours a day and made a SOFA. If they were to make the sofa in 3 days, how many hours of work is required to be put by them per day?

12. If ½ Dozen mangoes  Rs. 72. How much will 3 ¾ dozen mangoes cost?

13. Decimals : Convert 1/ 8 and 1/12  into a decimal

14. (Use BODMAS) and Simplify:   200² + 200/ 200 = ?

15. 0.006 × ? = 600

16. 64 - 48 ÷ 6 × 4 + 8

17. 0.2 + 1.3 - 0.4 × 1.5

18. 8{1 - {3 + (5 - 6 + 7)}}

Average:

19. Find the average of the first 5 Two digit prime numbers

20. The mean weight of 6 boys in a group is 48 kg. If five students of the group weigh 51 kg, 45 kg, 49 kg, 46 kg and 44 kg, find the weight of the sixth boy 

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Answer

1.	984310 -103489 =880821, 10,8 7,799
2	99 =XCIX, 1009= MIX
3	B-- b) the number increases-   5236
4	24  ( 48 x 8 / 16= 24)
5		  36 minutes
6			Rs.   60.60
7			LCM of 1240 and 5300 = ( 2 x 31) x (2 x 2 x 5 x 5 x 53) = 328,600
8			The greatest common factor of 20 and 24 is the product of all common factors 2 x 2 = 4.
9			240 ( LCM)
10			CP is. Rs. 90,000, Profit is Rs. 9000 hence SP is Rs. 99000
11			8 hours a day
12			1 mango is Rs.12  and hence 3 ¾ = 36 +9 = 45 x 12= Rs.540
13			0.125 and 0.833
14			=200(200+1)/200=201
15			(600/6) × 1000 = 100000
16			40
17			0.9
18			10
19			11+13+17+19+23 = 83/ 5 = 16.6
20			Let the weight of sixth boy be xMean of 6 boys=sum of 6 boystotal no. of boys⇒48=51+45+49+46+44+x6⇒48×6=51+45+49+46+44+x⇒288=235+x⇒x=288−235⇒x=53thus, the weight of sixth boy is 53.