RIMC- 2017 Revision Word Problem on Square with solution - FREE
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AREA-
Perimeter of SQUARE (15 May 2017)
First
5 questions 2 marks each, next by 8 marks each
Write
formula and steps for sum from 7 to 10 Draw
figures for all the sums.
1. What is
the Area of a Square whose one side is 2.25 m?
2. What is
the Perimeter of a square whose one side is 5.25 m?
3. Find the
side of the square whose area is 4225 Sq m?
4. Find the
Side of the square whose Perimeter is 380 cm.
5. Find the
Diagonal of a square whose one side is 10 m?
6. Find the
side of the square whose diagonal is 2 x 1.41 cm
7. Find the
cost of painting a square whose on side is 11.15 m, @ the cost of Rs.111 per sq
m
8. If a boy
ran around the square garden 15 times whose one side is 250m, what was the
total distance covered by him after 6 such rounds?
9. A boy
painted a Path of 2.5 m in the middle if a square garden of side 10 m. What is
the area painted by him?
10. Two Big
Squares of size 225 m in length and one of length 150 m was inside it, find the
area of the path between the two squares.
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Answers to the Problems on Square
Q.No
|
To Find what?
|
Steps
|
Answer
|
1
|
Area of Square
|
Side x side = 2.25 x 2.25 =
|
5.0625 Sq m
|
2
|
Perimeter
|
Side x 4 = 5.25 x 4 =
|
21 m
|
3
|
Side of square
|
Area given is 4225 sq m. find its √ to find the side
|
65 m
|
4
|
To find Side
|
Perimeter given as 380 m
|
95 m
|
5
|
Diagonal
|
Formula side √
2 side is 10 x√2 = 10 x 1. 414
To find the length of the diagonal of a
square, multiply the length of one side by the square root of 2:
|
14.14 m
|
6
|
Side
|
Diagonal given find the
side Formula SIDE √ 2
|
2 cm
|
7
|
Cost
|
Cost of painting the area l x
b x cost per sq m
|
13799.8 Rs.
|
8
|
Total distance
|
Find perimeter x 6 Time
|
6 km
|
9
|
Painting the path
|
2 .5 x 10 = 25 sq.m
|
25 sq.m
|
10
|
Area of outer-inner square
|
(225 x 225 ) – (150 x
150) = 50625 – 22500 = 28125 Sq m
|
28125 Sq m
|
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