All India Sainik School Entrance Guide with 10 years Solved papers

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All India Sainik School Entrance Guide with 10 years Solved papers

TARGET - SAINIK / RMS 2018- Entrance SKILL BUILDER GUIDES

 This is a new kit published by SAINIK ACADEMYCONTENTS:- Previous 10 Years Question Papers of:-

1. Mathematics 2006 to 2016
2. English 2006 to 2016
3. Intelligence Test 2006 to 2016
4. Complete solutions of Mathematics 2006 to 2016
5. Complete solutions of English 2006 to 2016
6. Complete solutions of Intelligence Test 2006 to 2016

Total No: Of books -03
Price Rs.1200 only Including Speed Charges
The Solution Books also contain : Formulae and explanations
+ Bonus On-line Entrance Exam Preparation
Sample Questions and Answers Given in the book
The Book has a General Section that tells you about how to prepare what to study?
Skill builder questions starts from

Easy

Moderate and

Achievers Section

We feel only those boys who score well in Achievers Section Gain AdmissionHence the questions are given in step by step order of Difficulty.
Sample: Section wise Questions:-
Simple Interest::
Refer the below formulas and previous year questions.
Interest is defined as money charged for borrowing the money from someone/banks. There are four words mainly used in this category. Those are
a) Principal: It’s denoted by ‘P’. Principal is the amount of money borrowed for a certain time.
b) Rate of interest: It’s denoted by ‘R’. Money paid for Rs. 100 per year called rate of interest.
c) Amount: It’s denoted by ‘A’. The sum of Principal and interest is called amount.
d) Time: Denoted by ‘T’. It’s the period for which we borrowed money is called Time.
Simple interest is denoted by ‘SI’. If the interest is calculated on the amount which we borrowed at any rate of interest for any period of time is called simple interest.
SI = (P * T * R) / 100
A = P + SI
P = (100 * A) / (100 + RT)
SI = ART / (100 + RT)
P = (100 * SI) / TR
T = (100 * SI) / PR
R = (100 * SI) / PT
SI = Simple Interest; A = Amount; P = Principal; T = Time; R = Rate of interest

1. Anusha deposits an amount of Rs. 65800 to obtain a simple interest at the rate of 14% per annum for 4yr. What total amount will Anusha get at the end of 4 yr?

Solution: Given data P = 65,800/-, R = 14%, T = 4yr
Simple Interest = { 65800*14*4} / 100 = 36848
Therefore Amount = P + SI => 65800 + 36848 = Rs.102648

ACHIEVERS SECTION

2. Nandini borrowed some money at the rate of 6% per annum for the first 3yr, at the rate of 9% per annum for the next 5yr and at the rate of 13% per annum for the period beyond 8yr. If she pays a total interest of Rs. 8160 at the end of 11yr. how much money did she borrow?

Ans: C Solution: Assume sum borrowed = P
As per given data, {[P*6*3] / 100 + [P*9*5] / 100 + [P*13*3] / 100} = 8160
=> {18P + 45P + 39P} / 100 = 8160
=> 102P/100 = 8160
=> Answer: Rs. 8000