Answers to Speed, time and distance question for class vi to viii

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Defence Academy Coimbatore A leading coaching academy for Sainik, Military and RIMC Schools, NDA, IMA, AFCAT SSB, FSB Interview http://www.ssbcoaching.com call 094437 20076





Answers to Speed, time and distance question for class vi to viii
see my previous Blog
 of 12 Nov 2016
 


Solutions:
1. Solution:
Option(C) is correct
Distance = Speed × time
Here time = 2hr 45 min = 114114 hr
Distance = 4×114=114×114=11 km
New Speed =16.5 kmph
Therefore time = DS=1116.5=40 min


2. Solution:
Option(D) is correct
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 954×60954×60 = 10 min.

3. Solution:
Option(A) is correct
In same time, they cover 110 km and 90 km respectively.
For the same time speed and distance is inversely proportional.
So ratio of their speed = 110:90110:90 = 11: 9

4. Solution:
Option(B) is correct
Time = 5060=565060=56 hr
Speed = 48 mph
Distance  = S×T=48×56=40S×T=48×56=40 km
Time = 40604060 hr
New speed = 40×32=6040×32=60 kmph


5. Solution:
Option(B) is correct
Let total distance =D=D
Distance travelled at 4 kmph speed =(23)D=(23)D
Distance travelled at 5 kmph speed =(1−23)D=(13)D=(1−23)D=(13)D
Total time =1 hr 24 min = (60+24) min =8460=8460 hr =2115=2115 hr 
We know,
Time=Distance / Speed   & Time=Distance/ Speed
Total time
2115=2/34D+1/35D2115=2/34D+1/35D
2115=2D12+D152115=2D12+D15
84=14D84=14D
D=6 km



6. Explanation:
Speed =
http://www.indiabix.com/_files/images/aptitude/1-sym-oparen-h1.gif
600
http://www.indiabix.com/_files/images/aptitude/1-sym-cparen-h1.gifm/sec.
5 x 60
   = 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
   =
http://www.indiabix.com/_files/images/aptitude/1-sym-oparen-h1.gif
2 x
18
http://www.indiabix.com/_files/images/aptitude/1-sym-cparen-h1.gif
km/hr
5
   = 7.2 km/hr.


7. Sachin can cover a distance in 1hr 24 min by covering 2/3 of the distance at 4 kmph and the rest at 5 kmph. The total distance is?

Let total distance =D=D
Distance travelled at 4 kmph speed =(23)D=(23)D
Distance travelled at 5 kmph speed =(1−23)D=(13)D=(1−23)D=(13)D
Total time =1 hr 24 min = (60+24) min =8460=8460 hr =2115=2115 hr 
We know,
Time=Distance/Speed;  Time=Distance/Speed
Total time
2115=2/34D+1/35D2115=2/34D+1/35D
2115=2D12+D152115=2D12+D15
84=14D84=14D
D=6 km

Answer  7 : He takes 3 minutes or to travel a distance of 2.1 kilometers.

8 He can travel 28.3 kilometers in 1 hour 53 minutes.

9. It takes 2 hours 1 minutes or 2s to travel a distance of 199.7 kilometers.

10. It can travel 2085.3 kilometers in 2 hours 16 minutes.





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call 094437 20076
visit
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