SAINIK – RMS – RIMC Preparation Maths By defence academy Coimbatore

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SAINIK – RMS – RIMC Preparation Maths By defence academy Coimbatore

5 marks each 30 minutes time

Solve the following:

1.  (1 ¾ - 1/8) + (5/6 ÷ 2/3) =?

2. a) Factorize: 3x -6y +ax -2ay

2. b) Find the square root of 256 and 169

3. Find the (a) Area (b) Perimeter of a Rectangle whose

Length is 5.5m and breadth is 250cm.

4. What would be the Opposite side of Triangle ABC where in the Angle B is 90 degrees. And side AC is 10 cm, and side BC is 80mm.

5. A Man bought a car for Rs.1, 25,000, got is repaired for Rs.20, 000. If he wants to make a gain of 12.5 % gain on its sales. What should its selling price be?

Write with steps. Where ever required

Step 1. What is given (Data)?

Step 2. What is required to be found out?

Step 3. Is there a need to convert the units?

Step 4. Formula to be used.

Step 5. Working

Step 6. Answer. (Answer should be written in full and should be underlined)

Solution:

The Candidate must solve the problem step by step.

This helps in recapture, Recheck,

Conversion of units. Before writing the final answer.

Unless they do it this way they may not be able to score perfect score

Where ever drawing is required, the candidate must draw so that his understanding become better.

Always be as neat as possible, so the person who corrects the question is able to understand and correct the paper.

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Now let us see how it can be done.

Let us take an example of question number 5.

First write the question. Correctly, ( This is to be done during practice session)

 5. A Man bought a car for Rs.1, 25,000, got is repaired for Rs.20, 000. If he wants to make a gain of 12.5 % gain on its sales. What should its selling price be?

Solution:

Step 1. What is given (write all the data given in the problem)

              a) Purchase price of the car is   Rs.1, 25, 000

              b) Cost of Repair of the car is    Rs.    20, 000

(Now Deduction. Therefore the CP is   Rs. 1, 45, 000)

Must make a profit of                                12. 5 % on the Sale

Step 2. What is to be found out?

          To find the Selling price of the car.

Step 3. What is required?

             First find the actual CP (Purchase price + Repair and other expenses)

   Formula to be used:  GAIN / 100 * CP

Total Gain = GAIN / 100 * CP

12.5/ 100 * 145000

12.5/100 * 145000    

Ie. 12.5 x 1450=Rs.18, 125 ( Total Gain on Sale)

Now add this to CP to get the final selling price

Ie. 18125 + 1,45,000 = Rs. 1,63, 125 Answer

(In this formula you will get the overall gain. On obtaining the gain you will have to add this gain to the CP to arrive at the Selling Price)

Or another formula is  

Selling Price is = (100 +Gain % / 100) * CP

(By using this formula you will get the SP)

Step 4. Working:

(100 + 12.5/ 100) * 145000

112.5 / 100 or 1125/ 1000 * 145000

Or 1125 * 145 =Rs. 1,63,125

Answer: Therefore the selling price of the car should be Rs. 1,63,125