How To score more in Maths Examination ?

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How to crack RIMC Maths


Sainik Academy Coimbatore ( 094437 20076)

offers Self Study guides for RIMC- RMS_ SAINIK Entrance Examinations

Example  of  Solved Mathematical Problems:-

. A reduction of 5% in the Price of sugar enables a man to buy 1 kg more for Rs. 304, find the original rate per kg and the reduced rate per kg.

Solution to Q

S.No:
Step
Working
1
1. What is given?
Amount available is Rs. 304 sugar bought x kg. on 5% reduction you get 1 more kg

2.To find
To find the Original rate of sugar, and reduced price per kg.

3.Formula
Let the original rate be Rs. X per kg.
Reduced rate = 100-5= 95% of Rs.5 – Per kg.
95/100 x = 19x / 20 per kg
Quantity of Sugar or Rs. 304 at Rs. X per kg =304/ x
Quantity of Sugar of Rs. 304 at Rs.19x / 20 per kg = (304 x 20)/ 19 x
304x 20-304x19 = 19x     Or 304=19x =
Original Price  = Rs. 16 per kg
Reduced Price =19x 16 / 20 = Rs. 15. 20  per kg

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