Model revision paper- Sainik Class VI
All India Sainik School Entrance Examination Revision Test Dec 2014
Five marks each 20 x 5 = 100
1.
What
will be the Simple Interest on Rs. 462.50 for 3 ½ Years at the rate of 4 % per
annum?
2.
On
selling an article for Rs. 75. Akil loses 6 ¼ %, then find the cost price of
the article.
3.
Which
is the least 6 digit number that is exactly divisible by 83?
4.
A,
B and C have a total of Rs. 1771. The ratio of the money between A and B is 5 :
7, If C has Rs. 571, calculate A and B’s share.
( sainik 2008)
5.
A
boy spends 1/3 of his money in a shop, then he goes to another shop and spends
½ of that was left. He is left with Rs. 15.
Find out how much total money did he have?( Sainik 2008)
Answer:-
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Q.No
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Explanation
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Step 1.
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Given: P= Rs. 462.50, T= 3.5 Years, R
= 4 %
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Step 2.
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To find: Simple Interest
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Step 3.
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Formula: Simple Interest = ( PxNxR) /
100
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Step 4.
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Working: substitute the values in the
formula
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 This can be written
as  ( as we are removing
the Decimals in the numerator we have
to multiply the same in the Denominator) |
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Q.No 2
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Solution
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Step 1.
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Given Selling Price; Rs. 75, Loss =
6.25%
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Step 2.
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To find the Cost Price.
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Step 3.
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Formula to be used= ( Loss X 100)/
Cost price
Let us take cost price as Rs. 100 loss
= 6.25,
Hence selling Price= Rs. 100 -6.25 =
Rs.93.75
Ie. For 93.75---------- CP = Rs. 100]
 For 75.00-----------Cp = X
( By cross multiplying we get)
 |
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Q.No
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Solution
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Step 1
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Given the greatest 6 digit no: is
999999, to be divided by 83
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Step 2
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To Find the exact 6 digit number that
is just below 999999 which is exactly divisible
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Step 3
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Formula: This can be done by dividing
999999 by 83, and subtract the remainder from 999999
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Step 4
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Working:- 999999 Divided by 83 Gives Quotient as 12048 and Remainder as 15
999999- 15 – 999984 is the greatest
Six digit number that can be divided by 83 without any remainder
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Q. 4: A Rs.
500 and B Rs. 700
Q.5 Rs. 45
for study kit
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